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(** In this file, we make a few simple observations about schedules with replacements. *)SectionReplaceAtFacts.(** For any given type of jobs... *)Context {Job : JobType}.(** ... and any given type of processor states, ... *)Context {PState: ProcessorState Job}.(** ...consider any given reference schedule. *)Variablesched: schedule PState.(** Suppose we are given a specific time [t'] ... *)Variablet': instant.(** ...and a replacement state [state]. *)Variablenstate: PState.(** In the following, let [sched'] denote the schedule with replacement at time t'. *)Letsched' := replace_at sched t' nstate.(** We begin with the trivial observation that [replace_at sched t' nstate] indeed returns [nstate] at time [t']. *)
bymove/eqP in TT; rewrite TT in DIFF; contradiction.Qed.(** As a result, the service in intervals that do not intersect with [t'] is invariant, too. *)
apply /andP; bysplit.Qed.(** Next, we consider the amount of service received in intervals that do span across the replacement point. We can relate the service received in the original and the new schedules by adding the service in the respective "missing" state... *)
byrewrite service_delta// addnK.Qed.(** As another simple invariant (useful for case analysis), we observe that if a job is scheduled neither in the replaced nor in the new state, then at any time it receives exactly the same amount of service in the new schedule with replacements as in the original schedule. *)
rewrite rest_of_schedule_invariant//.Qed.(** Based on the previous observation, we can trivially lift the invariant that jobs not involved in the replacement receive equal service to the cumulative service received in any interval. *)