Library prosa.analysis.abstract.lower_bound_on_service
Require Export prosa.analysis.facts.model.service_of_jobs.
Require Export prosa.analysis.facts.preemption.rtc_threshold.job_preemptable.
Require Export prosa.analysis.abstract.definitions.
Require Export prosa.analysis.abstract.busy_interval.
Require Export prosa.analysis.facts.preemption.rtc_threshold.job_preemptable.
Require Export prosa.analysis.abstract.definitions.
Require Export prosa.analysis.abstract.busy_interval.
Lower Bound On Job Service
In this section we prove that if the cumulative interference inside a busy interval is bounded by a certain constant then a job executes long enough to reach a specified amount of service.
Consider any type of tasks ...
... and any type of jobs associated with these tasks.
Context {Job : JobType}.
Context `{JobTask Job Task}.
Context `{JobArrival Job}.
Context `{JobCost Job}.
Context `{JobTask Job Task}.
Context `{JobArrival Job}.
Context `{JobCost Job}.
In addition, we assume existence of a function mapping jobs to
their preemption points.
Consider any kind of processor state model.
Consider any arrival sequence with consistent arrivals ...
Variable arr_seq : arrival_sequence Job.
Hypothesis H_arrival_times_are_consistent : consistent_arrival_times arr_seq.
Hypothesis H_arrival_times_are_consistent : consistent_arrival_times arr_seq.
... and any schedule of this arrival sequence.
Assume that the job costs are no larger than the task costs.
Let tsk be any task that is to be analyzed.
Assume we are provided with abstract functions for interference
and interfering workload.
We assume that the schedule is work-conserving.
Variable j : Job.
Hypothesis H_j_arrives : arrives_in arr_seq j.
Hypothesis H_job_of_tsk : job_of_task tsk j.
Hypothesis H_job_cost_positive : job_cost_positive j.
Hypothesis H_j_arrives : arrives_in arr_seq j.
Hypothesis H_job_of_tsk : job_of_task tsk j.
Hypothesis H_job_cost_positive : job_cost_positive j.
In this section, we show that the cumulative interference is a
complement to the total time where job j is scheduled inside a
busy interval prefix.
Consider any busy interval prefix
[t1, t2)
of job j.
Consider any sub-interval
[t, t + δ)
inside the busy interval [t1, t2)
.
Variables (t : instant) (δ : duration).
Hypothesis H_t1_le_t : t1 ≤ t.
Hypothesis H_tδ_le_t2 : t + δ ≤ t2.
Hypothesis H_t1_le_t : t1 ≤ t.
Hypothesis H_tδ_le_t2 : t + δ ≤ t2.
We prove that sum of cumulative service and cumulative
interference in the interval
[t, t + δ)
is equal to
δ.
Lemma interference_is_complement_to_schedule :
service_during sched j t (t + δ) + cumulative_interference j t (t + δ) ≥ δ.
Proof.
rewrite /service_during /cumulative_interference /service_at.
rewrite -big_split //= -{1}(sum_of_ones t δ) big_nat [in X in _ ≤ X]big_nat leq_sum // ⇒ x /andP[Lo Hi].
move: (H_work_conserving j t1 t2 x) ⇒ Workj.
feed_n 4 Workj; rt_eauto.
{ by apply/andP; split; eapply leq_trans; rt_eauto. }
destruct interference; first by lia.
by rewrite // addn0; apply Workj.
Qed.
service_during sched j t (t + δ) + cumulative_interference j t (t + δ) ≥ δ.
Proof.
rewrite /service_during /cumulative_interference /service_at.
rewrite -big_split //= -{1}(sum_of_ones t δ) big_nat [in X in _ ≤ X]big_nat leq_sum // ⇒ x /andP[Lo Hi].
move: (H_work_conserving j t1 t2 x) ⇒ Workj.
feed_n 4 Workj; rt_eauto.
{ by apply/andP; split; eapply leq_trans; rt_eauto. }
destruct interference; first by lia.
by rewrite // addn0; apply Workj.
Qed.
Also, note that under the unit-service processor model
assumption, the sum of service within the interval
[t, t + δ)
and the cumulative interference within the same interval
is bounded by the length of the interval (i.e., δ).
Remark service_and_interference_bounded :
unit_service_proc_model PState →
service_during sched j t (t + δ) + cumulative_interference j t (t + δ) ≤ δ.
Proof.
move ⇒ UNIT.
rewrite /service_during /cumulative_interference/service_at -big_split //=.
rewrite -{2}(sum_of_ones t δ).
rewrite big_nat [in X in _ ≤ X]big_nat; apply leq_sum ⇒ x /andP[Lo Hi].
move: (H_work_conserving j t1 t2 x) ⇒ Workj.
feed_n 4 Workj; try done.
{ by apply/andP; split; lia. }
destruct interference.
- rewrite addn1 ltnS.
by move_neq_up NE; apply Workj.
- by rewrite addn0; apply UNIT.
Qed.
End InterferenceIsComplement.
unit_service_proc_model PState →
service_during sched j t (t + δ) + cumulative_interference j t (t + δ) ≤ δ.
Proof.
move ⇒ UNIT.
rewrite /service_during /cumulative_interference/service_at -big_split //=.
rewrite -{2}(sum_of_ones t δ).
rewrite big_nat [in X in _ ≤ X]big_nat; apply leq_sum ⇒ x /andP[Lo Hi].
move: (H_work_conserving j t1 t2 x) ⇒ Workj.
feed_n 4 Workj; try done.
{ by apply/andP; split; lia. }
destruct interference.
- rewrite addn1 ltnS.
by move_neq_up NE; apply Workj.
- by rewrite addn0; apply UNIT.
Qed.
End InterferenceIsComplement.
In this section, we prove a sufficient condition under which job
j receives enough service.
Consider any busy interval
[t1, t2)
of job j.
Let progress_of_job be the desired service of job j.
Variable progress_of_job : duration.
Hypothesis H_progress_le_job_cost : progress_of_job ≤ job_cost j.
Hypothesis H_progress_le_job_cost : progress_of_job ≤ job_cost j.
Variable δ : duration.
Hypothesis H_total_workload_is_bounded :
progress_of_job + cumulative_interference j t1 (t1 + δ) ≤ δ.
Hypothesis H_total_workload_is_bounded :
progress_of_job + cumulative_interference j t1 (t1 + δ) ≤ δ.
Then, it must be the case that the job has received no less
service than progress_of_job.
Theorem j_receives_enough_service :
service sched j (t1 + δ) ≥ progress_of_job.
Proof.
destruct (leqP (t1 + δ) t2) as [NEQ|NEQ]; last first.
{ move: (job_completes_within_busy_interval _ _ _ _ H_busy_interval) ⇒ COMPL.
apply leq_trans with (job_cost j); first by done.
rewrite /service -(service_during_cat _ _ _ t2); last by apply/andP; split; last apply ltnW.
by apply leq_trans with (service_during sched j 0 t2); [done | rewrite leq_addr].
}
{ move: H_total_workload_is_bounded ⇒ BOUND.
rewrite addnC in BOUND; apply leq_subRL_impl in BOUND.
apply leq_trans with (δ - cumulative_interference j t1 (t1 + δ)); first by done.
apply leq_trans with (service_during sched j t1 (t1 + δ)).
- eapply leq_trans.
+ by apply leq_sub2r, (interference_is_complement_to_schedule t1 t2);
[apply H_busy_interval | apply leqnn | apply NEQ].
+ by rewrite -addnBA // subnn addn0 //.
- rewrite /service -[X in _ ≤ X](service_during_cat _ _ _ t1); first by rewrite leq_addl //.
by apply/andP; split; last rewrite leq_addr.
}
Qed.
End InterferenceBoundedImpliesEnoughService.
End LowerBoundOnService.
service sched j (t1 + δ) ≥ progress_of_job.
Proof.
destruct (leqP (t1 + δ) t2) as [NEQ|NEQ]; last first.
{ move: (job_completes_within_busy_interval _ _ _ _ H_busy_interval) ⇒ COMPL.
apply leq_trans with (job_cost j); first by done.
rewrite /service -(service_during_cat _ _ _ t2); last by apply/andP; split; last apply ltnW.
by apply leq_trans with (service_during sched j 0 t2); [done | rewrite leq_addr].
}
{ move: H_total_workload_is_bounded ⇒ BOUND.
rewrite addnC in BOUND; apply leq_subRL_impl in BOUND.
apply leq_trans with (δ - cumulative_interference j t1 (t1 + δ)); first by done.
apply leq_trans with (service_during sched j t1 (t1 + δ)).
- eapply leq_trans.
+ by apply leq_sub2r, (interference_is_complement_to_schedule t1 t2);
[apply H_busy_interval | apply leqnn | apply NEQ].
+ by rewrite -addnBA // subnn addn0 //.
- rewrite /service -[X in _ ≤ X](service_during_cat _ _ _ t1); first by rewrite leq_addl //.
by apply/andP; split; last rewrite leq_addr.
}
Qed.
End InterferenceBoundedImpliesEnoughService.
End LowerBoundOnService.