Library prosa.analysis.abstract.restricted_supply.abstract_rta

Abstract Response-Time Analysis for Restricted-Supply Processors (aRSA)

In this section we propose a general framework for response-time analysis (RTA) for real-time tasks with arbitrary arrival models under uni-processor scheduling subject to supply restrictions, characterized by a given SBF.
We prove that the maximum (with respect to the set of offsets) among the solutions of the response-time bound recurrence is a response-time bound for tsk. Note that in this section we add additional restrictions on the processor state. These assumptions allow us to eliminate the second equation from aRTA+'s recurrence since jobs experience delays only due to the lack of supply while executing non-preemptively.
Consider any type of tasks with a run-to-completion threshold ...
  Context {Task : TaskType}.
  Context `{TaskCost Task}.
  Context `{TaskRunToCompletionThreshold Task}.

... and any type of jobs associated with these tasks.
  Context {Job : JobType}.
  Context `{JobTask Job Task}.
  Context `{JobArrival Job}.
  Context `{JobCost Job}.
  Context `{JobPreemptable Job}.

Consider any kind of fully supply-consuming unit-supply processor state model.
Consider any valid arrival sequence.
Consider any restricted supply uniprocessor schedule of this arrival sequence ...
... where jobs do not execute before their arrival nor after completion.
Assume we are given valid WCETs for all tasks.
Consider a task set ts...
  Variable ts : list Task.

... and a task tsk of ts that is to be analyzed.
  Variable tsk : Task.
  Hypothesis H_tsk_in_ts : tsk \in ts.

Consider a valid preemption model ...
...and a valid task run-to-completion threshold function. That is, task_rtc tsk is (1) no bigger than tsk's cost and (2) for any job j of task tsk job_rtct j is bounded by task_rtct tsk.
Assume we are provided with abstract functions for Interference and Interfering Workload.
  Context `{Interference Job}.
  Context `{InterferingWorkload Job}.

We assume that the scheduler is work-conserving.
Let L be a constant that bounds any busy interval of task tsk.
  Variable L : duration.
  Hypothesis H_busy_interval_exists :
    busy_intervals_are_bounded_by arr_seq sched tsk L.

Consider a valid, unit supply-bound function SBF. That is, (1) SBF 0 = 0, (2) for any duration Δ, the supply produced during a busy interval of length Δ is at least SBF Δ, and (3) SBF makes steps of at most one.
Next, we assume that intra_IBF is a bound on the intra-supply interference incurred by task tsk.
Given any job j of task tsk that arrives exactly A units after the beginning of the busy interval, the bound on the interference incurred by j within an interval of length Δ is no greater than (Δ - SBF Δ) + intra_IBF A Δ.
  Let IBF_P (A Δ : duration) :=
    (Δ - SBF Δ) + intra_IBF A Δ.

Next, we instantiate function IBF_NP, which is a function that bounds interference in a non-preemptive stage of execution. We prove that this function can be instantiated as λ tsk F Δ (F - task_rtct tsk) + (Δ - SBF Δ - (F - SBF F)).
Let us reiterate on the intuitive interpretation of this function. Since F is a solution to the first equation task_rtct tsk + IBF_P A F F, we know that by time instant t1 + F a job receives task_rtct tsk units of service and, hence, it becomes non-preemptive. Knowing this information, how can we bound the job's interference in an interval [t1, t1 + Δ)>>? Note that this interval starts with the beginning of the busy interval. We know that the job receives F - task_rtct tsk units of interference. In the non-preemptive mode, a job under analysis can still experience some interference due to a lack of supply. This interference is bounded by (Δ - SBF Δ) - (F - SBF F) since part of this interference has already been accounted for in the preemptive part of the execution (F - SBF F).
  Let IBF_NP (F Δ : duration) :=
    (F - task_rtct tsk) + (Δ - SBF Δ - (F - SBF F)).

In the next section, we prove a few helper lemmas.
  Section AuxiliaryLemmas.

Consider any job j of tsk.
      Variable j : Job.
      Hypothesis H_j_arrives : arrives_in arr_seq j.
      Hypothesis H_job_of_tsk : job_of_task tsk j.
      Hypothesis H_job_cost_positive : job_cost_positive j.

Consider the busy interval [t1, t2) of job j.
      Variable t1 t2 : instant.
      Hypothesis H_busy_interval : busy_interval_prefix sched j t1 t2.

Let's define A as a relative arrival time of job j (with respect to time t1).
      Let A : duration := job_arrival j - t1.

Consider an arbitrary time Δ ...
      Variable Δ : duration.
... such that t1 + Δ is inside the busy interval...
      Hypothesis H_inside_busy_interval : t1 + Δ < t2.
... the job j is not completed by time (t1 + Δ).
      Hypothesis H_job_j_is_not_completed : ~~ completed_by sched j (t1 + Δ).

First, we show that blackout is counted as interference.
      Lemma blackout_impl_interference :
         t,
          t1 t < t2
          is_blackout sched t
          interference j t.
      Proof.
        movet /andP [LE1 LE2].
        apply contraLR ⇒ /negP INT.
        eapply H_work_conserving in INT =>//; last by lia.
        by apply/negPn; eapply pos_service_impl_pos_supply.
      Qed.

Next, we show that interference is equal to a sum of two functions: is_blackout and intra_interference.
      Lemma blackout_plus_local_is_interference :
         t,
          t1 t < t2
          is_blackout sched t + intra_interference sched j t
          = interference j t.
      Proof.
        movet t_INT.
        rewrite /intra_interference /cond_interference.
        destruct (is_blackout sched t) eqn:BLACKOUT; rewrite (negbRL BLACKOUT) //.
        by rewrite blackout_impl_interference.
      Qed.

As a corollary, cumulative interference during a time interval [t1, t1 + Δ) can be split into a sum of total blackouts in [t1, t1 + Δ) and cumulative intra-supply interference during [t1, t1 + Δ).
      Corollary blackout_plus_local_is_interference_cumul :
        blackout_during sched t1 (t1 + Δ) + cumul_intra_interference sched j t1 (t1 + Δ)
        = cumulative_interference j t1 (t1 + Δ).
      Proof.
        rewrite -big_split; apply eq_big_nat ⇒ //=.
        movet /andP [t_GEQ t_LTN_td].
        move: (ltn_trans t_LTN_td H_inside_busy_interval) ⇒ t_LTN_t2.
        by apply blackout_plus_local_is_interference; apply /andP.
      Qed.

Moreover, since the total blackout duration in an interval of length Δ is bounded by Δ - SBF Δ, the cumulative interference during the time interval [t1, t1 + Δ) is bounded by the sum of Δ - SBF Δ and cumulative intra-supply interference during [t1, t1 + Δ).
      Corollary cumulative_job_interference_bound :
        cumulative_interference j t1 (t1 + Δ)
         (Δ - SBF Δ) + cumul_intra_interference sched j t1 (t1 + Δ).
      Proof.
        rewrite -blackout_plus_local_is_interference_cumul leq_add2r.
        by apply: blackout_during_bound ⇒ //.
      Qed.

Next, consider a duration F such that F Δ and job j has enough service to become non-preemptive by time instant t1 + F.
      Variable F : duration.
      Hypothesis H_F_le_Δ : F Δ.
      Hypothesis H_enough_service : task_rtct tsk service sched j (t1 + F).

Then, we show that job j does not experience any intra-supply interference in the time interval [t1 + F, t1 + Δ)>>.
      Lemma no_intra_interference_after_F :
        cumul_intra_interference sched j (t1 + F) (t1 + Δ) = 0.
      Proof.
        rewrite /cumul_intra_interference/ cumul_cond_interference big_nat.
        apply big1; movet /andP [GE__t LT__t].
        apply/eqP; rewrite eqb0; apply/negP.
        move ⇒ /andP [P /negPn /negP D]; apply: D; apply/negP.
        eapply H_work_conserving with (t1 := t1) (t2 := t2); eauto 2.
        { by apply/andP; split; lia. }
        eapply progress_inside_supplies; eauto.
        eapply job_nonpreemptive_after_run_to_completion_threshold; eauto 2.
        - rewrite -(leqRW H_enough_service).
          by apply H_valid_run_to_completion_threshold.
        - move: H_job_j_is_not_completed; apply contra.
          by apply completion_monotonic; lia.
      Qed.

  End AuxiliaryLemmas.

For clarity, let's define a local name for the search space.
We use the following equation to bound the response-time of a job of task tsk. Consider any value R that upper-bounds the solution of each response-time recurrence, i.e., for any relative arrival time A in the search space, there exists a corresponding solution F such that (1) F A + R, (2) task_rtct tsk + intra_IBF tsk A F SBF F and SBF F + (task_cost tsk - task_rtct tsk) SBF (A + R).
Note that, compared to "ideal RTA," there is an additional requirement F A + R. Intuitively, it is needed to rule out a nonsensical situation when the non-preemptive stage completes earlier than the preemptive stage.
  Variable R : duration.
  Hypothesis H_R_is_maximum_rs :
     (A : duration),
      is_in_search_space_rs A
       (F : duration),
        F A + R
         task_rtct tsk + intra_IBF A F SBF F
         SBF F + (task_cost tsk - task_rtct tsk) SBF (A + R).

In the following section we prove that all the premises of abstract RTA are satisfied.
  Section RSaRTAPremises.

First, we show that IBF_P correctly upper-bounds interference in the preemptive stage of execution.
    Lemma IBF_P_bounds_interference :
      job_interference_is_bounded_by
        arr_seq sched tsk IBF_P (relative_arrival_time_of_job_is_A sched).
    Proof.
      movet1 t2 Δ j ARR TSK BUSY LT NCOM A PAR; move: (PAR _ _ BUSY) ⇒ EQ.
      rewrite fold_cumul_interference.
      rewrite (leqRW (cumulative_job_interference_bound _ _ _ _ _ t2 _ _ _ _)) ⇒ //.
      - rewrite leq_add2l /cumul_intra_interference.
        by apply: H_intra_supply_interference_is_bounded ⇒ //.
      - by eapply incomplete_implies_positive_cost ⇒ //.
      - by apply BUSY.
    Qed.

Next, we prove that IBF_NP correctly bounds interference in the non-preemptive stage given a solution to the preemptive stage F.
    Lemma IBF_NP_bounds_interference :
      job_interference_is_bounded_by
        arr_seq sched tsk IBF_NP (relative_time_to_reach_rtct sched tsk IBF_P).
    Proof.
      have USER : unit_service_proc_model PState by apply unit_supply_is_unit_service.
      movet1 t2 Δ j ARR TSK BUSY LT NCOM F RT.
      have POS := incomplete_implies_positive_cost _ _ _ NCOM.
      move: (RT _ _ BUSY) (BUSY) ⇒ [FIX RTC] [[/andP [LE1 LE2] _] _].
      have RleF : task_rtct tsk F.
      { apply cumulative_service_ge_delta with (j := j) (t := t1) (sched := sched) ⇒ //.
        rewrite -[X in _ X]add0n.
        by erewrite <-cumulative_service_before_job_arrival_zero;
          first erewrite service_during_cat with (t1 := 0) ⇒ //; auto; lia. }
      rewrite /IBF_NP addnBAC // leq_subRL_impl // addnC.
      have [NEQ1|NEQ1] := leqP t2 (t1 + F); last have [NEQ2|NEQ2] := leqP F Δ.
      { rewrite -leq_subLR in NEQ1.
        rewrite -{1}(leqRW NEQ1) (leqRW RTC) (leqRW (service_at_most_cost _ _ _ _ _)) ⇒ //.
        rewrite (leqRW (cumulative_interference_sub _ _ _ _ t1 t2 _ _)) ⇒ //.
        rewrite (leqRW (service_within_busy_interval_ge_job_cost _ _ _ _ _ _ _)) ⇒ //.
        have LLL : (t1 < t2) by lia.
        interval_to_duration t1 t2 k.
        by rewrite addnC (leqRW (service_and_interference_bound _ _ _ _ _ _ _ _ _ _ _ _)) ⇒ //; lia. }
      { rewrite addnC -{1}(leqRW FIX) -addnA leq_add2l /IBF_P.
        rewrite (@addnC (_ - _) _) -addnA subnKC; last by apply complement_SBF_monotone.
        rewrite -/(cumulative_interference _ _ _).
        erewrite <-blackout_plus_local_is_interference_cumul with (t2 := t2) ⇒ //; last by apply BUSY.
        rewrite addnC leq_add //; last first.
        { by eapply blackout_during_bound with (t2 := t2) ⇒ //; apply BUSY. }
        rewrite /cumul_intra_interference (cumulative_interference_cat _ j (t1 + F)) //=; last by lia.
        rewrite -!/(cumul_intra_interference _ _ _ _).
        rewrite (no_intra_interference_after_F _ _ _ _ _ t2) //; last by move: BUSY ⇒ [].
        rewrite addn0 //; eapply H_intra_supply_interference_is_bounded ⇒ //.
        - by move : NCOM; apply contra, completion_monotonic; lia.
        - movet1' t2' BUSY'.
          have [EQ1 E2] := busy_interval_is_unique _ _ _ _ _ _ BUSY BUSY'.
          by subst; lia. }
      { rewrite addnC (leqRW RTC); eapply leq_trans.
        - by erewrite leq_add2l; apply cumulative_interference_sub with (bl := t1) (br := t1 + F); lia.
        - erewrite no_service_before_busy_interval ⇒ //.
          by rewrite (leqRW (service_and_interference_bound _ _ _ _ _ _ _ _ _ _ _ _)) ⇒ //; lia. }
    Qed.

Next, we prove that F is bounded by task_cost tsk + IBF_NP F Δ for any F and Δ. As explained in file analysis/abstract/abstract_rta, this shows that the second stage indeed takes into account service received in the first stage.
    Lemma IBF_P_sol_le_IBF_NP :
       (F Δ : duration),
        F task_cost tsk + IBF_NP F Δ.
    Proof.
      moveF Δ.
      have [NEQ|NEQ] := leqP F (task_rtct tsk).
      - apply: leq_trans; [apply NEQ | ].
        by apply: leq_trans; [apply H_valid_run_to_completion_threshold | lia].
      - rewrite addnA (@addnBCA _ F _); try lia.
        by apply H_valid_run_to_completion_threshold; lia.
    Qed.

Next we prove that H_R_is_maximum_rs implies H_R_is_maximum.
    Lemma max_in_rs_hypothesis_impl_max_in_arta_hypothesis :
       (A : duration),
        is_in_search_space L IBF_P A
         (F : duration),
          task_rtct tsk + (F - SBF F + intra_IBF A F) F
           task_cost tsk + (F - task_rtct tsk + (A + R - SBF (A + R) - (F - SBF F))) A + R.
    Proof.
      moveA SP.
      case: (H_R_is_maximum_rs A SP) ⇒ [F [EQ0 [EQ1 EQ2]]].
       F; split.
      { have → : a b c, a + (b + c) = (a + c) + b by lia.
        have -T : a b c, c b (a c - b) (a + b c); [by lia | apply: T; first by lia].
        have LE : SBF F F by eapply sbf_bounded_by_duration; eauto.
        by rewrite (leqRW EQ1); lia.
      }
      { have JJ := IBF_P_sol_le_IBF_NP F (A + R); rewrite /IBF_NP in JJ.
        rewrite addnA; rewrite addnA in JJ.
        have T: a b c, c b (a c - b) (a + b c); [by lia | apply: T; first by lia].
        rewrite subnA; [ | by apply complement_SBF_monotone | by lia].
        have LE : Δ, SBF Δ Δ by move ⇒ ?; eapply sbf_bounded_by_duration; eauto.
        rewrite subKn; last by eauto.
        have T: a b c d e, b e b c e + (a - c) d a + (b - c) d + (b - e) by lia.
        apply : T ⇒ //.
        eapply leq_trans; last by apply LE.
        by rewrite -(leqRW EQ1); lia.
      }
    Qed.

  End RSaRTAPremises.

Finally, we apply the uniprocessor_response_time_bound theorem, and using the lemmas above, we prove that all the requirements are satisfied. So, R is a response time bound.